IsDeleteRevision

ShapeBase.IsDeleteRevision property

Returns true if this object was deleted in Microsoft Word while change tracking was enabled.

public bool IsDeleteRevision { get; }

Examples

Shows how to work with revision shapes.

Document doc = new Document();

Assert.False(doc.TrackRevisions);

// Insert an inline shape without tracking revisions, which will make this shape not a revision of any kind.
Shape shape = new Shape(doc, ShapeType.Cube);
shape.WrapType = WrapType.Inline;
shape.Width = 100.0;
shape.Height = 100.0;
doc.FirstSection.Body.FirstParagraph.AppendChild(shape);

// Start tracking revisions and then insert another shape, which will be a revision.
doc.StartTrackRevisions("John Doe");

shape = new Shape(doc, ShapeType.Sun);
shape.WrapType = WrapType.Inline;
shape.Width = 100.0;
shape.Height = 100.0;
doc.FirstSection.Body.FirstParagraph.AppendChild(shape);

Shape[] shapes = doc.GetChildNodes(NodeType.Shape, true).OfType<Shape>().ToArray();

Assert.AreEqual(2, shapes.Length);

shapes[0].Remove();

// Since we removed that shape while we were tracking changes,
// the shape persists in the document and counts as a delete revision.
// Accepting this revision will remove the shape permanently, and rejecting it will keep it in the document.
Assert.AreEqual(ShapeType.Cube, shapes[0].ShapeType);
Assert.True(shapes[0].IsDeleteRevision);

// And we inserted another shape while tracking changes, so that shape will count as an insert revision.
// Accepting this revision will assimilate this shape into the document as a non-revision,
// and rejecting the revision will remove this shape permanently.
Assert.AreEqual(ShapeType.Sun, shapes[1].ShapeType);
Assert.True(shapes[1].IsInsertRevision);

See Also

ShapeBase.IsDecorative ShapeBase.IsGroup